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13204331410001 is a prime number
BaseRepresentation
bin1100000000100101111101…
…1110111011001001010001
31201202022200120002122021112
43000021133132323021101
53212314432320110001
644025552555503105
72531660433052034
oct300113736731121
951668616078245
1013204331410001
114230a1a932386
121593107a57a95
1374a217473794
1433914348901b
1517d71cee6cbb
hexc025f7bb251

13204331410001 has 2 divisors, whose sum is σ = 13204331410002. Its totient is φ = 13204331410000.

The previous prime is 13204331409991. The next prime is 13204331410033. The reversal of 13204331410001 is 10001413340231.

13204331410001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7376085651025 + 5828245758976 = 2715895^2 + 2414176^2 .

It is a cyclic number.

It is not a de Polignac number, because 13204331410001 - 222 = 13204327215697 is a prime.

It is not a weakly prime, because it can be changed into another prime (13204331410201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602165705000 + 6602165705001.

It is an arithmetic number, because the mean of its divisors is an integer number (6602165705001).

Almost surely, 213204331410001 is an apocalyptic number.

It is an amenable number.

13204331410001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13204331410001 is an equidigital number, since it uses as much as digits as its factorization.

13204331410001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 13204331410001 its reverse (10001413340231), we get a palindrome (23205744750232).

The spelling of 13204331410001 in words is "thirteen trillion, two hundred four billion, three hundred thirty-one million, four hundred ten thousand, one".