132043330203041 has 4 divisors (see below), whose sum is σ = 132216843121284. Its totient is φ = 131869817284800.

The previous prime is 132043330202951. The next prime is 132043330203077. The reversal of 132043330203041 is 140302033340231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 64991732445025 + 67051597758016 = 8061745^2 + 8188504^2 .

It is a cyclic number.

It is not a de Polignac number, because 132043330203041 - 2²⁶ = 132043263094177 is a prime.

It is a super-2 number, since 2×132043330203041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132043330202995 and 132043330203013.

It is not an unprimeable number, because it can be changed into a prime (132043330209041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86756457980 + ... + 86756459501.

It is an arithmetic number, because the mean of its divisors is an integer number (33054210780321).

Almost surely, 2^{132043330203041} is an apocalyptic number.

It is an amenable number.

132043330203041 is a deficient number, since it is larger than the sum of its proper divisors (173512918243).

132043330203041 is an equidigital number, since it uses as much as digits as its factorization.

132043330203041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 173512918242.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 132043330203041 its reverse (140302033340231), we get a palindrome (272345363543272).

The spelling of 132043330203041 in words is "one hundred thirty-two trillion, forty-three billion, three hundred thirty million, two hundred three thousand, forty-one".