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132043545451 = 1319100108829
BaseRepresentation
bin111101011111001101…
…0001001101101101011
3110121211100020002222101
41322332122021231223
54130411121423301
6140354315234231
712353106421546
oct1727632115553
9417740202871
10132043545451
1150aaa159074
1221711148977
13c5b438741c
146568a5b85d
15367c478701
hex1ebe689b6b

132043545451 has 4 divisors (see below), whose sum is σ = 132143655600. Its totient is φ = 131943435304.

The previous prime is 132043545419. The next prime is 132043545457. The reversal of 132043545451 is 154545340231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132043545451 - 25 = 132043545419 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132043545451.

It is not an unprimeable number, because it can be changed into a prime (132043545457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50053096 + ... + 50055733.

It is an arithmetic number, because the mean of its divisors is an integer number (33035913900).

Almost surely, 2132043545451 is an apocalyptic number.

132043545451 is a deficient number, since it is larger than the sum of its proper divisors (100110149).

132043545451 is a wasteful number, since it uses less digits than its factorization.

132043545451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100110148.

The product of its (nonzero) digits is 144000, while the sum is 37.

Adding to 132043545451 its reverse (154545340231), we get a palindrome (286588885682).

The spelling of 132043545451 in words is "one hundred thirty-two billion, forty-three million, five hundred forty-five thousand, four hundred fifty-one".

Divisors: 1 1319 100108829 132043545451