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132044030214400 = 2852147120696779
BaseRepresentation
bin11110000001011111100101…
…100001000000000100000000
3122022112021201111110210001101
4132001133211201000010000
5114301402133213330100
61144500105015144144
736545603106644533
oct3601374541000400
9568467644423041
10132044030214400
1139089616747857
1212987026675054
13588a910b3bc55
142486d72596a1a
15103eb7cca086a
hex7817e5840100

132044030214400 has 216 divisors, whose sum is σ = 327258129139200. Its totient is φ = 52748413132800.

The previous prime is 132044030214373. The next prime is 132044030214409. The reversal of 132044030214400 is 4412030440231.

It is a super-2 number, since 2×1320440302144002 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (132044030214409) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19478390211 + ... + 19478396989.

It is an arithmetic number, because the mean of its divisors is an integer number (1515083931200).

Almost surely, 2132044030214400 is an apocalyptic number.

132044030214400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132044030214400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (163629064569600).

132044030214400 is an abundant number, since it is smaller than the sum of its proper divisors (195214098924800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132044030214400 is a wasteful number, since it uses less digits than its factorization.

132044030214400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10345 (or 10326 counting only the distinct ones).

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 132044030214400 its reverse (4412030440231), we get a palindrome (136456060654631).

The spelling of 132044030214400 in words is "one hundred thirty-two trillion, forty-four billion, thirty million, two hundred fourteen thousand, four hundred".