Base | Representation |
---|---|
bin | 11000100110000101… |
… | …10011011110110111 |
3 | 1021002020102020020121 |
4 | 30103002303132313 |
5 | 204020311413101 |
6 | 10022132112411 |
7 | 645134404051 |
oct | 142302633667 |
9 | 37066366217 |
10 | 13204404151 |
11 | 56665a6304 |
12 | 2686165707 |
13 | 132583b7c3 |
14 | 8d39768d1 |
15 | 52437b0a1 |
hex | 3130b37b7 |
13204404151 has 4 divisors (see below), whose sum is σ = 13630352704. Its totient is φ = 12778455600.
The previous prime is 13204404137. The next prime is 13204404209. The reversal of 13204404151 is 15140440231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13204404151 - 223 = 13196015543 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13204404131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212974230 + ... + 212974291.
It is an arithmetic number, because the mean of its divisors is an integer number (3407588176).
Almost surely, 213204404151 is an apocalyptic number.
13204404151 is a deficient number, since it is larger than the sum of its proper divisors (425948553).
13204404151 is an equidigital number, since it uses as much as digits as its factorization.
13204404151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 425948552.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 13204404151 its reverse (15140440231), we get a palindrome (28344844382).
The spelling of 13204404151 in words is "thirteen billion, two hundred four million, four hundred four thousand, one hundred fifty-one".
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