Base | Representation |
---|---|
bin | 1100000000100110010000… |
… | …1110101101000010001111 |
3 | 1201202022220002221110120021 |
4 | 3000021210032231002033 |
5 | 3212320113211401413 |
6 | 44030004522403011 |
7 | 2531662420662055 |
oct | 300114416550217 |
9 | 51668802843507 |
10 | 13204411043983 |
11 | 4230a60883595 |
12 | 159312a660467 |
13 | 74a22ab06393 |
14 | 33914dc981d5 |
15 | 17d724ec718d |
hex | c02643ad08f |
13204411043983 has 2 divisors, whose sum is σ = 13204411043984. Its totient is φ = 13204411043982.
The previous prime is 13204411043951. The next prime is 13204411044049. The reversal of 13204411043983 is 38934011440231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13204411043983 - 25 = 13204411043951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13204411043683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602205521991 + 6602205521992.
It is an arithmetic number, because the mean of its divisors is an integer number (6602205521992).
Almost surely, 213204411043983 is an apocalyptic number.
13204411043983 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204411043983 is an equidigital number, since it uses as much as digits as its factorization.
13204411043983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 248832, while the sum is 43.
The spelling of 13204411043983 in words is "thirteen trillion, two hundred four billion, four hundred eleven million, forty-three thousand, nine hundred eighty-three".
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