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13204411240001 = 53594222709063
BaseRepresentation
bin1100000000100110010000…
…1111011100111001000001
31201202022220010022102110012
43000021210033130321001
53212320113234140001
644030004530514305
72531662422436412
oct300114417347101
951668803272405
1013204411240001
114230a609a7893
12159312a735995
1374a22ab74677
1433914dd09809
1517d7250152bb
hexc02643dce41

13204411240001 has 8 divisors (see below), whose sum is σ = 13681577367360. Its totient is φ = 12735690530992.

The previous prime is 13204411239977. The next prime is 13204411240019. The reversal of 13204411240001 is 10004211440231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13204411240001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13204411240021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2111351405 + ... + 2111357658.

It is an arithmetic number, because the mean of its divisors is an integer number (1710197170920).

Almost surely, 213204411240001 is an apocalyptic number.

It is an amenable number.

13204411240001 is a deficient number, since it is larger than the sum of its proper divisors (477166127359).

13204411240001 is an equidigital number, since it uses as much as digits as its factorization.

13204411240001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4222709175.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13204411240001 its reverse (10004211440231), we get a palindrome (23208622680232).

The spelling of 13204411240001 in words is "thirteen trillion, two hundred four billion, four hundred eleven million, two hundred forty thousand, one".

Divisors: 1 53 59 3127 4222709063 223803580339 249139834717 13204411240001