Base | Representation |
---|---|
bin | 11110000001011111101010… |
… | …011101010011101101111010 |
3 | 122022112021221021111110011210 |
4 | 132001133222131103231322 |
5 | 114301402320430214120 |
6 | 1144500121140303550 |
7 | 36545605134513153 |
oct | 3601375235235572 |
9 | 568467837443153 |
10 | 132044113132410 |
11 | 39089659531336 |
12 | 1298704a3a1bb6 |
13 | 588a92508156b |
14 | 2486d7d5bc92a |
15 | 103eb851cdce0 |
hex | 7817ea753b7a |
132044113132410 has 32 divisors (see below), whose sum is σ = 316914921513792. Its totient is φ = 35210757946880.
The previous prime is 132044113132367. The next prime is 132044113132429. The reversal of 132044113132410 is 14231311440231.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 61778871 + ... + 63880490.
It is an arithmetic number, because the mean of its divisors is an integer number (9903591297306).
Almost surely, 2132044113132410 is an apocalyptic number.
132044113132410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132044113132410 is an abundant number, since it is smaller than the sum of its proper divisors (184870808381382).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132044113132410 is a wasteful number, since it uses less digits than its factorization.
132044113132410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125694398.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 132044113132410 its reverse (14231311440231), we get a palindrome (146275424572641).
The spelling of 132044113132410 in words is "one hundred thirty-two trillion, forty-four billion, one hundred thirteen million, one hundred thirty-two thousand, four hundred ten".
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