Base | Representation |
---|---|
bin | 11110000001011111101100… |
… | …010000110011101111011111 |
3 | 122022112022000101110201102022 |
4 | 132001133230100303233133 |
5 | 114301402401203111033 |
6 | 1144500124141250355 |
7 | 36545605653046346 |
oct | 3601375420635737 |
9 | 568468011421368 |
10 | 132044143410143 |
11 | 39089674631458 |
12 | 129870585639bb |
13 | 588a92b422a93 |
14 | 2486d83620b5d |
15 | 103eb87bb0098 |
hex | 7817ec433bdf |
132044143410143 has 2 divisors, whose sum is σ = 132044143410144. Its totient is φ = 132044143410142.
The previous prime is 132044143410121. The next prime is 132044143410161. The reversal of 132044143410143 is 341014341440231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132044143410143 - 28 = 132044143409887 is a prime.
It is a super-2 number, since 2×1320441434101432 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132044143410103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022071705071 + 66022071705072.
It is an arithmetic number, because the mean of its divisors is an integer number (66022071705072).
Almost surely, 2132044143410143 is an apocalyptic number.
132044143410143 is a deficient number, since it is larger than the sum of its proper divisors (1).
132044143410143 is an equidigital number, since it uses as much as digits as its factorization.
132044143410143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 132044143410143 its reverse (341014341440231), we get a palindrome (473058484850374).
The spelling of 132044143410143 in words is "one hundred thirty-two trillion, forty-four billion, one hundred forty-three million, four hundred ten thousand, one hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •