Base | Representation |
---|---|
bin | 1100000000100110010001… |
… | …1011101010111000001111 |
3 | 1201202022220100100011011122 |
4 | 3000021210123222320033 |
5 | 3212320120044134043 |
6 | 44030005123311155 |
7 | 2531662461606566 |
oct | 300114433527017 |
9 | 51668810304148 |
10 | 13204414443023 |
11 | 4230a62795311 |
12 | 159312b81b4bb |
13 | 74a22b72654b |
14 | 339150500bdd |
15 | 17d725449368 |
hex | c02646eae0f |
13204414443023 has 2 divisors, whose sum is σ = 13204414443024. Its totient is φ = 13204414443022.
The previous prime is 13204414442987. The next prime is 13204414443089. The reversal of 13204414443023 is 32034441440231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13204414443023 - 28 = 13204414442767 is a prime.
It is a super-2 number, since 2×132044144430232 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13204414443223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602207221511 + 6602207221512.
It is an arithmetic number, because the mean of its divisors is an integer number (6602207221512).
Almost surely, 213204414443023 is an apocalyptic number.
13204414443023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204414443023 is an equidigital number, since it uses as much as digits as its factorization.
13204414443023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 110592, while the sum is 35.
Adding to 13204414443023 its reverse (32034441440231), we get a palindrome (45238855883254).
The spelling of 13204414443023 in words is "thirteen trillion, two hundred four billion, four hundred fourteen million, four hundred forty-three thousand, twenty-three".
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