Base | Representation |
---|---|
bin | 11110000001011111110110… |
… | …110111000100010000011111 |
3 | 122022112022110210000221220220 |
4 | 132001133312313010100133 |
5 | 114301403232212231143 |
6 | 1144500153532212423 |
7 | 36545613242246415 |
oct | 3601376667042037 |
9 | 568468423027826 |
10 | 132044321211423 |
11 | 39089755a32165 |
12 | 129870a800a113 |
13 | 588a959206c3a |
14 | 2486d9d0a52b5 |
15 | 103eb985d1d83 |
hex | 7817f6dc441f |
132044321211423 has 8 divisors (see below), whose sum is σ = 176062970779008. Its totient is φ = 88027609559064.
The previous prime is 132044321211421. The next prime is 132044321211457. The reversal of 132044321211423 is 324112123440231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132044321211423 - 21 = 132044321211421 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132044321211421) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 484319811 + ... + 484592372.
It is an arithmetic number, because the mean of its divisors is an integer number (22007871347376).
Almost surely, 2132044321211423 is an apocalyptic number.
132044321211423 is a deficient number, since it is larger than the sum of its proper divisors (44018649567585).
132044321211423 is an equidigital number, since it uses as much as digits as its factorization.
132044321211423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 968957613.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 132044321211423 its reverse (324112123440231), we get a palindrome (456156444651654).
The spelling of 132044321211423 in words is "one hundred thirty-two trillion, forty-four billion, three hundred twenty-one million, two hundred eleven thousand, four hundred twenty-three".
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