Base | Representation |
---|---|
bin | 11110000001100000111001… |
… | …101010101110011111101111 |
3 | 122022112102100220002110102221 |
4 | 132001200321222232133233 |
5 | 114301413031131100111 |
6 | 1144500501051500211 |
7 | 36545653102233436 |
oct | 3601407152563757 |
9 | 568472326073387 |
10 | 132045442050031 |
11 | 3908a18068a864 |
12 | 1298735b457667 |
13 | 588aaa74a2953 |
14 | 2487067caa11d |
15 | 103ec11bd2371 |
hex | 781839aae7ef |
132045442050031 has 2 divisors, whose sum is σ = 132045442050032. Its totient is φ = 132045442050030.
The previous prime is 132045442049999. The next prime is 132045442050083. The reversal of 132045442050031 is 130050244540231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132045442050031 - 25 = 132045442049999 is a prime.
It is a super-2 number, since 2×1320454420500312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132045442057031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022721025015 + 66022721025016.
It is an arithmetic number, because the mean of its divisors is an integer number (66022721025016).
Almost surely, 2132045442050031 is an apocalyptic number.
132045442050031 is a deficient number, since it is larger than the sum of its proper divisors (1).
132045442050031 is an equidigital number, since it uses as much as digits as its factorization.
132045442050031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 132045442050031 its reverse (130050244540231), we get a palindrome (262095686590262).
The spelling of 132045442050031 in words is "one hundred thirty-two trillion, forty-five billion, four hundred forty-two million, fifty thousand, thirty-one".
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