Base | Representation |
---|---|
bin | 11110000001100110011111… |
… | …010111101101110110111101 |
3 | 122022112222212010112001111011 |
4 | 132001212133113231312331 |
5 | 114302012323441410023 |
6 | 1144503332351355221 |
7 | 36546254603140303 |
oct | 3601463727556675 |
9 | 568488763461434 |
10 | 132051443310013 |
11 | 390917801a1257 |
12 | 12988555222b11 |
13 | 588b5228c0066 |
14 | 2487476d26273 |
15 | 103ee639b850d |
hex | 78199f5eddbd |
132051443310013 has 2 divisors, whose sum is σ = 132051443310014. Its totient is φ = 132051443310012.
The previous prime is 132051443309993. The next prime is 132051443310029. The reversal of 132051443310013 is 310013344150231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 121510012292964 + 10541431017049 = 11023158^2 + 3246757^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132051443310013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132051443340013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66025721655006 + 66025721655007.
It is an arithmetic number, because the mean of its divisors is an integer number (66025721655007).
Almost surely, 2132051443310013 is an apocalyptic number.
It is an amenable number.
132051443310013 is a deficient number, since it is larger than the sum of its proper divisors (1).
132051443310013 is an equidigital number, since it uses as much as digits as its factorization.
132051443310013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 132051443310013 its reverse (310013344150231), we get a palindrome (442064787460244).
The spelling of 132051443310013 in words is "one hundred thirty-two trillion, fifty-one billion, four hundred forty-three million, three hundred ten thousand, thirteen".
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