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132052054403 = 181253728551
BaseRepresentation
bin111101011111011101…
…0100111000110000011
3110121211221020102001202
41322332322213012003
54130420311220103
6140355221451415
712353241641153
oct1727672470603
9417757212052
10132052054403
1151003a3aa65
1221713b70b6b
13c5b60763c9
146569c34763
15367d0a9988
hex1ebeea7183

132052054403 has 4 divisors (see below), whose sum is σ = 132052964208. Its totient is φ = 132051144600.

The previous prime is 132052054373. The next prime is 132052054427. The reversal of 132052054403 is 304450250231.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 304450250231 = 1117327248747.

It is a cyclic number.

It is not a de Polignac number, because 132052054403 - 230 = 130978312579 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132052054493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183023 + ... + 545528.

It is an arithmetic number, because the mean of its divisors is an integer number (33013241052).

Almost surely, 2132052054403 is an apocalyptic number.

132052054403 is a deficient number, since it is larger than the sum of its proper divisors (909805).

132052054403 is an equidigital number, since it uses as much as digits as its factorization.

132052054403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 909804.

The product of its (nonzero) digits is 14400, while the sum is 29.

The spelling of 132052054403 in words is "one hundred thirty-two billion, fifty-two million, fifty-four thousand, four hundred three".

Divisors: 1 181253 728551 132052054403