Base | Representation |
---|---|
bin | 11110000001100111011010… |
… | …110110100001110111101011 |
3 | 122022120002102200022022100102 |
4 | 132001213122312201313223 |
5 | 114302021344424234430 |
6 | 1144504015400500015 |
7 | 36546321411342251 |
oct | 3601473266416753 |
9 | 568502380268312 |
10 | 132052441243115 |
11 | 39092142533158 |
12 | 1298879347a60b |
13 | 588b651585513 |
14 | 248752d6965d1 |
15 | 103eec13dc345 |
hex | 7819dada1deb |
132052441243115 has 4 divisors (see below), whose sum is σ = 158462929491744. Its totient is φ = 105641952994488.
The previous prime is 132052441243031. The next prime is 132052441243133. The reversal of 132052441243115 is 511342144250231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132052441243115 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13205244124307 + ... + 13205244124316.
It is an arithmetic number, because the mean of its divisors is an integer number (39615732372936).
Almost surely, 2132052441243115 is an apocalyptic number.
132052441243115 is a deficient number, since it is larger than the sum of its proper divisors (26410488248629).
132052441243115 is an equidigital number, since it uses as much as digits as its factorization.
132052441243115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26410488248628.
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 132052441243115 its reverse (511342144250231), we get a palindrome (643394585493346).
The spelling of 132052441243115 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred forty-one million, two hundred forty-three thousand, one hundred fifteen".
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