Base | Representation |
---|---|
bin | 111101011111011110… |
… | …0001010010110110111 |
3 | 110121211222000001210021 |
4 | 1322332330022112313 |
5 | 4130420412222413 |
6 | 140355234310011 |
7 | 12353245253422 |
oct | 1727674122667 |
9 | 417758001707 |
10 | 132052460983 |
11 | 51004198483 |
12 | 21714128307 |
13 | c5b61894a1 |
14 | 6569cdc9b9 |
15 | 367d13a18d |
hex | 1ebef0a5b7 |
132052460983 has 2 divisors, whose sum is σ = 132052460984. Its totient is φ = 132052460982.
The previous prime is 132052460921. The next prime is 132052461001. The reversal of 132052460983 is 389064250231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132052460983 - 233 = 123462526391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132052460783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026230491 + 66026230492.
It is an arithmetic number, because the mean of its divisors is an integer number (66026230492).
Almost surely, 2132052460983 is an apocalyptic number.
132052460983 is a deficient number, since it is larger than the sum of its proper divisors (1).
132052460983 is an equidigital number, since it uses as much as digits as its factorization.
132052460983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 43.
The spelling of 132052460983 in words is "one hundred thirty-two billion, fifty-two million, four hundred sixty thousand, nine hundred eighty-three".
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