Base | Representation |
---|---|
bin | 111101011111100001… |
… | …0011101000011110101 |
3 | 110121212002002212102202 |
4 | 1322333002131003311 |
5 | 4130421323013303 |
6 | 140355333514245 |
7 | 12353265263366 |
oct | 1727702350365 |
9 | 417762085382 |
10 | 132054110453 |
11 | 51005114781 |
12 | 217147a2985 |
13 | c5b66161c5 |
14 | 656a20bb6d |
15 | 367d363c88 |
hex | 1ebf09d0f5 |
132054110453 has 2 divisors, whose sum is σ = 132054110454. Its totient is φ = 132054110452.
The previous prime is 132054110443. The next prime is 132054110537. The reversal of 132054110453 is 354011450231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68991851569 + 63062258884 = 262663^2 + 251122^2 .
It is a cyclic number.
It is not a de Polignac number, because 132054110453 - 28 = 132054110197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132054110443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66027055226 + 66027055227.
It is an arithmetic number, because the mean of its divisors is an integer number (66027055227).
Almost surely, 2132054110453 is an apocalyptic number.
It is an amenable number.
132054110453 is a deficient number, since it is larger than the sum of its proper divisors (1).
132054110453 is an equidigital number, since it uses as much as digits as its factorization.
132054110453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 132054110453 its reverse (354011450231), we get a palindrome (486065560684).
The spelling of 132054110453 in words is "one hundred thirty-two billion, fifty-four million, one hundred ten thousand, four hundred fifty-three".
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