Base | Representation |
---|---|
bin | 111101011111100011… |
… | …0101001110100101111 |
3 | 110121212011011210112021 |
4 | 1322333012221310233 |
5 | 4130422113230221 |
6 | 140355413251011 |
7 | 12353310530032 |
oct | 1727706516457 |
9 | 417764153467 |
10 | 132055211311 |
11 | 510057a6881 |
12 | 21715033a67 |
13 | c5b69102ba |
14 | 656a417019 |
15 | 367d4d0041 |
hex | 1ebf1a9d2f |
132055211311 has 2 divisors, whose sum is σ = 132055211312. Its totient is φ = 132055211310.
The previous prime is 132055211303. The next prime is 132055211359. The reversal of 132055211311 is 113112550231.
It is a weak prime.
It is an emirp because it is prime and its reverse (113112550231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132055211311 - 23 = 132055211303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132055211381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66027605655 + 66027605656.
It is an arithmetic number, because the mean of its divisors is an integer number (66027605656).
Almost surely, 2132055211311 is an apocalyptic number.
132055211311 is a deficient number, since it is larger than the sum of its proper divisors (1).
132055211311 is an equidigital number, since it uses as much as digits as its factorization.
132055211311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 132055211311 its reverse (113112550231), we get a palindrome (245167761542).
The spelling of 132055211311 in words is "one hundred thirty-two billion, fifty-five million, two hundred eleven thousand, three hundred eleven".
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