Base | Representation |
---|---|
bin | 111101011111100011… |
… | …0111111111010100101 |
3 | 110121212011100101122121 |
4 | 1322333012333322211 |
5 | 4130422124124142 |
6 | 140355415225541 |
7 | 12353311354606 |
oct | 1727706777245 |
9 | 417764311577 |
10 | 132055301797 |
11 | 51005858861 |
12 | 217150782b1 |
13 | c5b6942543 |
14 | 656a43bdad |
15 | 367d4ebc67 |
hex | 1ebf1bfea5 |
132055301797 has 2 divisors, whose sum is σ = 132055301798. Its totient is φ = 132055301796.
The previous prime is 132055301773. The next prime is 132055301863. The reversal of 132055301797 is 797103550231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128507193441 + 3548108356 = 358479^2 + 59566^2 .
It is a cyclic number.
It is not a de Polignac number, because 132055301797 - 27 = 132055301669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132055301197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66027650898 + 66027650899.
It is an arithmetic number, because the mean of its divisors is an integer number (66027650899).
Almost surely, 2132055301797 is an apocalyptic number.
It is an amenable number.
132055301797 is a deficient number, since it is larger than the sum of its proper divisors (1).
132055301797 is an equidigital number, since it uses as much as digits as its factorization.
132055301797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 198450, while the sum is 43.
The spelling of 132055301797 in words is "one hundred thirty-two billion, fifty-five million, three hundred one thousand, seven hundred ninety-seven".
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