Base | Representation |
---|---|
bin | 10011001101110111110… |
… | …001110010011111100001 |
3 | 11200020121102002022111221 |
4 | 103031313301302133201 |
5 | 133114004003003244 |
6 | 2450354200135041 |
7 | 164256551022235 |
oct | 23156761623741 |
9 | 4606542068457 |
10 | 1320564500449 |
11 | 46a059262807 |
12 | 193b26467481 |
13 | 976b471b6bc |
14 | 47cb68165c5 |
15 | 2453e4ea784 |
hex | 13377c727e1 |
1320564500449 has 4 divisors (see below), whose sum is σ = 1323572620480. Its totient is φ = 1317556380420.
The previous prime is 1320564500429. The next prime is 1320564500483. The reversal of 1320564500449 is 9440054650231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1320564500449 - 213 = 1320564492257 is a prime.
It is a super-2 number, since 2×13205645004492 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1320564500429) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1504059357 + ... + 1504060234.
It is an arithmetic number, because the mean of its divisors is an integer number (330893155120).
Almost surely, 21320564500449 is an apocalyptic number.
It is an amenable number.
1320564500449 is a deficient number, since it is larger than the sum of its proper divisors (3008120031).
1320564500449 is an equidigital number, since it uses as much as digits as its factorization.
1320564500449 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3008120030.
The product of its (nonzero) digits is 518400, while the sum is 43.
The spelling of 1320564500449 in words is "one trillion, three hundred twenty billion, five hundred sixty-four million, five hundred thousand, four hundred forty-nine".
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