Base | Representation |
---|---|
bin | 11110000001110010001101… |
… | …110111111000100110101111 |
3 | 122022121012100122100122011102 |
4 | 132001302031313320212233 |
5 | 114302214120332422024 |
6 | 1144513214023513315 |
7 | 36550211614613663 |
oct | 3601621567704657 |
9 | 568535318318142 |
10 | 132064034654639 |
11 | 3909705172989a |
12 | 1298aa89bb883b |
13 | 588c77b40c939 |
14 | 2487d0d2b68a3 |
15 | 104044e0e71ae |
hex | 781c8ddf89af |
132064034654639 has 2 divisors, whose sum is σ = 132064034654640. Its totient is φ = 132064034654638.
The previous prime is 132064034654569. The next prime is 132064034654663. The reversal of 132064034654639 is 936456430460231.
It is a strong prime.
It is an emirp because it is prime and its reverse (936456430460231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132064034654639 - 216 = 132064034589103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132064034654689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66032017327319 + 66032017327320.
It is an arithmetic number, because the mean of its divisors is an integer number (66032017327320).
Almost surely, 2132064034654639 is an apocalyptic number.
132064034654639 is a deficient number, since it is larger than the sum of its proper divisors (1).
132064034654639 is an equidigital number, since it uses as much as digits as its factorization.
132064034654639 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 33592320, while the sum is 56.
The spelling of 132064034654639 in words is "one hundred thirty-two trillion, sixty-four billion, thirty-four million, six hundred fifty-four thousand, six hundred thirty-nine".
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