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1320644551301 is a prime number
BaseRepresentation
bin10011001101111100100…
…011001010001010000101
311200020210222201022122022
4103031330203022022011
5133114140001120201
62450410140012525
7164261542316525
oct23157443121205
94606728638568
101320644551301
1146a09a469139
12193b49231145
13976c8198c7a
1447cc32d3685
152454655e41b
hex1337c8ca285

1320644551301 has 2 divisors, whose sum is σ = 1320644551302. Its totient is φ = 1320644551300.

The previous prime is 1320644551231. The next prime is 1320644551307. The reversal of 1320644551301 is 1031554460231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1229681388100 + 90963163201 = 1108910^2 + 301601^2 .

It is an emirp because it is prime and its reverse (1031554460231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1320644551301 - 230 = 1319570809477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320644551307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660322275650 + 660322275651.

It is an arithmetic number, because the mean of its divisors is an integer number (660322275651).

Almost surely, 21320644551301 is an apocalyptic number.

It is an amenable number.

1320644551301 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320644551301 is an equidigital number, since it uses as much as digits as its factorization.

1320644551301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

The spelling of 1320644551301 in words is "one trillion, three hundred twenty billion, six hundred forty-four million, five hundred fifty-one thousand, three hundred one".