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1320645339001 is a prime number
BaseRepresentation
bin10011001101111100100…
…110001010011101111001
311200020211001012100011101
4103031330212022131321
5133114140201322001
62450410204531401
7164261552110162
oct23157446123571
94606731170141
101320645339001
1146a09a956a2a
12193b49550b61
13976c83b3671
1447cc345a769
1524546667a01
hex1337c98a779

1320645339001 has 2 divisors, whose sum is σ = 1320645339002. Its totient is φ = 1320645339000.

The previous prime is 1320645338989. The next prime is 1320645339011. The reversal of 1320645339001 is 1009335460231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1205384410000 + 115260929001 = 1097900^2 + 339501^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320645339001 - 229 = 1320108468089 is a prime.

It is a super-3 number, since 3×13206453390013 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1320645339011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660322669500 + 660322669501.

It is an arithmetic number, because the mean of its divisors is an integer number (660322669501).

Almost surely, 21320645339001 is an apocalyptic number.

It is an amenable number.

1320645339001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320645339001 is an equidigital number, since it uses as much as digits as its factorization.

1320645339001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 58320, while the sum is 37.

The spelling of 1320645339001 in words is "one trillion, three hundred twenty billion, six hundred forty-five million, three hundred thirty-nine thousand, one".