Base | Representation |
---|---|
bin | 11000100110100101… |
… | …01000100000000001 |
3 | 1021002112020001001012 |
4 | 30103102220200001 |
5 | 204022342202343 |
6 | 10022401050305 |
7 | 645214565153 |
oct | 142322504001 |
9 | 37075201035 |
10 | 13208553473 |
11 | 566897a7a5 |
12 | 2687626995 |
13 | 132666231b |
14 | 8d4336ad3 |
15 | 5248ea718 |
hex | 3134a8801 |
13208553473 has 2 divisors, whose sum is σ = 13208553474. Its totient is φ = 13208553472.
The previous prime is 13208553409. The next prime is 13208553487. The reversal of 13208553473 is 37435580231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12809033329 + 399520144 = 113177^2 + 19988^2 .
It is a cyclic number.
It is not a de Polignac number, because 13208553473 - 26 = 13208553409 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13208553473.
It is not a weakly prime, because it can be changed into another prime (13208553403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6604276736 + 6604276737.
It is an arithmetic number, because the mean of its divisors is an integer number (6604276737).
Almost surely, 213208553473 is an apocalyptic number.
It is an amenable number.
13208553473 is a deficient number, since it is larger than the sum of its proper divisors (1).
13208553473 is an equidigital number, since it uses as much as digits as its factorization.
13208553473 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 302400, while the sum is 41.
The spelling of 13208553473 in words is "thirteen billion, two hundred eight million, five hundred fifty-three thousand, four hundred seventy-three".
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