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132100044042103 = 711860564000593
BaseRepresentation
bin11110000010010011110000…
…001100110010111101110111
3122022201122022012101001101121
4132002103300030302331313
5114303311342233321403
61144541531130004411
736552625144426624
oct3602236014627567
9568648265331347
10132100044042103
1139100350025645
1212995a59576707
135892c997a95b7
14248996789534b
15104135a5b03bd
hex7824f0332f77

132100044042103 has 4 divisors (see below), whose sum is σ = 133960608042768. Its totient is φ = 130239480041440.

The previous prime is 132100044042101. The next prime is 132100044042139. The reversal of 132100044042103 is 301240440001231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132100044042103 - 21 = 132100044042101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132100044042101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 930282000226 + ... + 930282000367.

It is an arithmetic number, because the mean of its divisors is an integer number (33490152010692).

Almost surely, 2132100044042103 is an apocalyptic number.

132100044042103 is a deficient number, since it is larger than the sum of its proper divisors (1860564000665).

132100044042103 is an equidigital number, since it uses as much as digits as its factorization.

132100044042103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1860564000664.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 132100044042103 its reverse (301240440001231), we get a palindrome (433340484043334).

The spelling of 132100044042103 in words is "one hundred thirty-two trillion, one hundred billion, forty-four million, forty-two thousand, one hundred three".

Divisors: 1 71 1860564000593 132100044042103