Base | Representation |
---|---|
bin | 1100000000111011001000… |
… | …0000111101101110110101 |
3 | 1201202212100101022100122102 |
4 | 3000032302000331232311 |
5 | 3212413100311020001 |
6 | 44032332325511445 |
7 | 2532251250050153 |
oct | 300166200755665 |
9 | 51685311270572 |
10 | 13210011032501 |
11 | 4233374930878 |
12 | 1594231b72585 |
13 | 74a91105855a |
14 | 3395218dc3d3 |
15 | 17d951947e6b |
hex | c03b203dbb5 |
13210011032501 has 2 divisors, whose sum is σ = 13210011032502. Its totient is φ = 13210011032500.
The previous prime is 13210011032489. The next prime is 13210011032509. The reversal of 13210011032501 is 10523011001231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8945781902500 + 4264229130001 = 2990950^2 + 2065001^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13210011032501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13210011032509) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605005516250 + 6605005516251.
It is an arithmetic number, because the mean of its divisors is an integer number (6605005516251).
Almost surely, 213210011032501 is an apocalyptic number.
It is an amenable number.
13210011032501 is a deficient number, since it is larger than the sum of its proper divisors (1).
13210011032501 is an equidigital number, since it uses as much as digits as its factorization.
13210011032501 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 13210011032501 its reverse (10523011001231), we get a palindrome (23733022033732).
The spelling of 13210011032501 in words is "thirteen trillion, two hundred ten billion, eleven million, thirty-two thousand, five hundred one".
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