Base | Representation |
---|---|
bin | 11000100110110000… |
… | …01111000010000001 |
3 | 1021002121222122111201 |
4 | 30103120033002001 |
5 | 204023231201032 |
6 | 10022452341201 |
7 | 645233222503 |
oct | 142330170201 |
9 | 37077878451 |
10 | 13210022017 |
11 | 5669793075 |
12 | 2688014801 |
13 | 1326a5789a |
14 | 8d45d9d73 |
15 | 524ada8e7 |
hex | 31360f081 |
13210022017 has 2 divisors, whose sum is σ = 13210022018. Its totient is φ = 13210022016.
The previous prime is 13210022011. The next prime is 13210022027. The reversal of 13210022017 is 71022001231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13188455281 + 21566736 = 114841^2 + 4644^2 .
It is a cyclic number.
It is not a de Polignac number, because 13210022017 - 219 = 13209497729 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13210021985 and 13210022003.
It is not a weakly prime, because it can be changed into another prime (13210022011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605011008 + 6605011009.
It is an arithmetic number, because the mean of its divisors is an integer number (6605011009).
Almost surely, 213210022017 is an apocalyptic number.
It is an amenable number.
13210022017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13210022017 is an equidigital number, since it uses as much as digits as its factorization.
13210022017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 19.
Adding to 13210022017 its reverse (71022001231), we get a palindrome (84232023248).
The spelling of 13210022017 in words is "thirteen billion, two hundred ten million, twenty-two thousand, seventeen".
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