Base | Representation |
---|---|
bin | 111101100000111010… |
… | …0101000001000000101 |
3 | 110121222022222211100011 |
4 | 1323001310220020011 |
5 | 4131020302124123 |
6 | 140404122550221 |
7 | 12354403264315 |
oct | 1730164501005 |
9 | 417868884304 |
10 | 132100817413 |
11 | 51029516374 |
12 | 21728368371 |
13 | c5c31ba766 |
14 | 65724c9445 |
15 | 36824dce0d |
hex | 1ec1d28205 |
132100817413 has 2 divisors, whose sum is σ = 132100817414. Its totient is φ = 132100817412.
The previous prime is 132100817351. The next prime is 132100817417. The reversal of 132100817413 is 314718001231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 118844288644 + 13256528769 = 344738^2 + 115137^2 .
It is a cyclic number.
It is not a de Polignac number, because 132100817413 - 221 = 132098720261 is a prime.
It is a super-2 number, since 2×1321008174132 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132100817417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050408706 + 66050408707.
It is an arithmetic number, because the mean of its divisors is an integer number (66050408707).
Almost surely, 2132100817413 is an apocalyptic number.
It is an amenable number.
132100817413 is a deficient number, since it is larger than the sum of its proper divisors (1).
132100817413 is an equidigital number, since it uses as much as digits as its factorization.
132100817413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 132100817413 its reverse (314718001231), we get a palindrome (446818818644).
The spelling of 132100817413 in words is "one hundred thirty-two billion, one hundred million, eight hundred seventeen thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •