Base | Representation |
---|---|
bin | 11110000010010100101001… |
… | …010000001100001001001101 |
3 | 122022201201202220111101102022 |
4 | 132002110221100030021031 |
5 | 114303320322303423343 |
6 | 1144542210121535525 |
7 | 36552660646422563 |
oct | 3602245120141115 |
9 | 568651686441368 |
10 | 132101001232973 |
11 | 391007a136a283 |
12 | 129960860445a5 |
13 | 58930bcba8426 |
14 | 2489a18a5ba33 |
15 | 10413b4637568 |
hex | 78252940c24d |
132101001232973 has 2 divisors, whose sum is σ = 132101001232974. Its totient is φ = 132101001232972.
The previous prime is 132101001232901. The next prime is 132101001233029. The reversal of 132101001232973 is 379232100101231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 71362249873924 + 60738751359049 = 8447618^2 + 7793507^2 .
It is a cyclic number.
It is not a de Polignac number, because 132101001232973 - 210 = 132101001231949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132101001262973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050500616486 + 66050500616487.
It is an arithmetic number, because the mean of its divisors is an integer number (66050500616487).
Almost surely, 2132101001232973 is an apocalyptic number.
It is an amenable number.
132101001232973 is a deficient number, since it is larger than the sum of its proper divisors (1).
132101001232973 is an equidigital number, since it uses as much as digits as its factorization.
132101001232973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 35.
The spelling of 132101001232973 in words is "one hundred thirty-two trillion, one hundred one billion, one million, two hundred thirty-two thousand, nine hundred seventy-three".
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