Base | Representation |
---|---|
bin | 10011001110010010011… |
… | …100110111100101111101 |
3 | 11200021202121010201001221 |
4 | 103032102130313211331 |
5 | 133120413033014044 |
6 | 2450510423433341 |
7 | 164303623512061 |
oct | 23162234674575 |
9 | 4607677121057 |
10 | 1321012001149 |
11 | 46a2689216a5 |
12 | 1940302b5851 |
13 | 97756351909 |
14 | 47d1a023aa1 |
15 | 24568943484 |
hex | 1339273797d |
1321012001149 has 2 divisors, whose sum is σ = 1321012001150. Its totient is φ = 1321012001148.
The previous prime is 1321012001093. The next prime is 1321012001201. The reversal of 1321012001149 is 9411002101231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1320465283225 + 546717924 = 1149115^2 + 23382^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1321012001149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321012005149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660506000574 + 660506000575.
It is an arithmetic number, because the mean of its divisors is an integer number (660506000575).
Almost surely, 21321012001149 is an apocalyptic number.
It is an amenable number.
1321012001149 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321012001149 is an equidigital number, since it uses as much as digits as its factorization.
1321012001149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 25.
The spelling of 1321012001149 in words is "one trillion, three hundred twenty-one billion, twelve million, one thousand, one hundred forty-nine".
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