1321023113 has 4 divisors (see below), whose sum is σ = 1323559188. Its totient is φ = 1318487040.

The previous prime is 1321023107. The next prime is 1321023133. The reversal of 1321023113 is 3113201231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 990801529 + 330221584 = 31477^2 + 18172^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1321023113 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1321023091 and 1321023100.

It is not an unprimeable number, because it can be changed into a prime (1321023133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1267256 + ... + 1268297.

It is an arithmetic number, because the mean of its divisors is an integer number (330889797).

Almost surely, 2^1321023113 is an apocalyptic number.

It is an amenable number.

1321023113 is a deficient number, since it is larger than the sum of its proper divisors (2536075).

1321023113 is an equidigital number, since it uses as much as digits as its factorization.

1321023113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2536074.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1321023113 is about 36345.8816511582. The cubic root of 1321023113 is about 1097.2446502690.

Adding to 1321023113 its reverse (3113201231), we get a palindrome (4434224344).

The spelling of 1321023113 in words is "one billion, three hundred twenty-one million, twenty-three thousand, one hundred thirteen".