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132103114433 = 2351461111611
BaseRepresentation
bin111101100000111110…
…1011000111011000001
3110121222111022112020222
41323001331120323001
54131021344130213
6140404244112425
712354431642213
oct1730175307301
9417874275228
10132103114433
115102a845134
1221729095715
13c5c3813144
1465729265b3
1536827e3808
hex1ec1f58ec1

132103114433 has 8 divisors (see below), whose sum is σ = 137850641856. Its totient is φ = 126355913200.

The previous prime is 132103114417. The next prime is 132103114439. The reversal of 132103114433 is 334411301231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132103114433 - 24 = 132103114417 is a prime.

It is a super-2 number, since 2×1321031144332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132103114439) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1127798 + ... + 1239408.

It is an arithmetic number, because the mean of its divisors is an integer number (17231330232).

Almost surely, 2132103114433 is an apocalyptic number.

It is an amenable number.

132103114433 is a deficient number, since it is larger than the sum of its proper divisors (5747527423).

132103114433 is a wasteful number, since it uses less digits than its factorization.

132103114433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 163095.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 132103114433 its reverse (334411301231), we get a palindrome (466514415664).

The spelling of 132103114433 in words is "one hundred thirty-two billion, one hundred three million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 23 51461 111611 1183603 2567053 5743613671 132103114433