132103402400041 has 4 divisors (see below), whose sum is σ = 139874190776532. Its totient is φ = 124332614023552.

The previous prime is 132103402400033. The next prime is 132103402400059. The reversal of 132103402400041 is 140004204301231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 47396615630400 + 84706786769641 = 6884520^2 + 9203629^2 .

It is not a de Polignac number, because 132103402400041 - 2³ = 132103402400033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132103402399979 and 132103402400015.

It is not an unprimeable number, because it can be changed into a prime (132103402400441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3885394188220 + ... + 3885394188253.

It is an arithmetic number, because the mean of its divisors is an integer number (34968547694133).

Almost surely, 2^{132103402400041} is an apocalyptic number.

It is an amenable number.

132103402400041 is a deficient number, since it is larger than the sum of its proper divisors (7770788376491).

132103402400041 is an equidigital number, since it uses as much as digits as its factorization.

132103402400041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7770788376490.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 132103402400041 its reverse (140004204301231), we get a palindrome (272107606701272).

The spelling of 132103402400041 in words is "one hundred thirty-two trillion, one hundred three billion, four hundred two million, four hundred thousand, forty-one".