132103421111041 has 4 divisors (see below), whose sum is σ = 132253028610352. Its totient is φ = 131953813611732.

The previous prime is 132103421111003. The next prime is 132103421111059. The reversal of 132103421111041 is 140111124301231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132103421111041 - 2¹¹ = 132103421108993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132103421110997 and 132103421111015.

It is not an unprimeable number, because it can be changed into a prime (132103421121041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74803748331 + ... + 74803750096.

It is an arithmetic number, because the mean of its divisors is an integer number (33063257152588).

Almost surely, 2^{132103421111041} is an apocalyptic number.

It is an amenable number.

132103421111041 is a deficient number, since it is larger than the sum of its proper divisors (149607499311).

132103421111041 is an equidigital number, since it uses as much as digits as its factorization.

132103421111041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149607499310.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 132103421111041 its reverse (140111124301231), we get a palindrome (272214545412272).

The spelling of 132103421111041 in words is "one hundred thirty-two trillion, one hundred three billion, four hundred twenty-one million, one hundred eleven thousand, forty-one".