1321040113 has 8 divisors (see below), whose sum is σ = 1391735520. Its totient is φ = 1250461440.

The previous prime is 1321040111. The next prime is 1321040137. The reversal of 1321040113 is 3110401231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1321040113 - 2¹ = 1321040111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1321040111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5443 + ... + 51688.

It is an arithmetic number, because the mean of its divisors is an integer number (173966940).

Almost surely, 2^1321040113 is an apocalyptic number.

It is an amenable number.

1321040113 is a deficient number, since it is larger than the sum of its proper divisors (70695407).

1321040113 is a wasteful number, since it uses less digits than its factorization.

1321040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 58367.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1321040113 is about 36346.1155145911. The cubic root of 1321040113 is about 1097.2493569944.

Adding to 1321040113 its reverse (3110401231), we get a palindrome (4431441344).

The spelling of 1321040113 in words is "one billion, three hundred twenty-one million, forty thousand, one hundred thirteen".