Base | Representation |
---|---|
bin | 11110000010010111100100… |
… | …100001101000010010101111 |
3 | 122022202000212212120000020111 |
4 | 132002113210201220102233 |
5 | 114303343241121102421 |
6 | 1144543450000000451 |
7 | 36553131550265425 |
oct | 3602274441502257 |
9 | 568660785500214 |
10 | 132104143144111 |
11 | 39102063947656 |
12 | 12996802300127 |
13 | 58934a0ab8b48 |
14 | 2489c36045115 |
15 | 10414ea3adee1 |
hex | 7825e48684af |
132104143144111 has 8 divisors (see below), whose sum is σ = 134357737852800. Its totient is φ = 129851033150040.
The previous prime is 132104143144079. The next prime is 132104143144151. The reversal of 132104143144111 is 111441341401231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132104143144111 - 25 = 132104143144079 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132104143144151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 120628905 + ... + 121719106.
It is an arithmetic number, because the mean of its divisors is an integer number (16794717231600).
Almost surely, 2132104143144111 is an apocalyptic number.
132104143144111 is a deficient number, since it is larger than the sum of its proper divisors (2253594708689).
132104143144111 is an equidigital number, since it uses as much as digits as its factorization.
132104143144111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 242357309.
The product of its (nonzero) digits is 4608, while the sum is 31.
Adding to 132104143144111 its reverse (111441341401231), we get a palindrome (243545484545342).
The spelling of 132104143144111 in words is "one hundred thirty-two trillion, one hundred four billion, one hundred forty-three million, one hundred forty-four thousand, one hundred eleven".
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