Base | Representation |
---|---|
bin | 11110000010010111101111… |
… | …111011010101100000110111 |
3 | 122022202001101012111110022122 |
4 | 132002113233323111200313 |
5 | 114303344134103313221 |
6 | 1144543520551550155 |
7 | 36553136362230113 |
oct | 3602275773254067 |
9 | 568661335443278 |
10 | 132104334432311 |
11 | 3910215191a27a |
12 | 1299685638b35b |
13 | 5893501612a27 |
14 | 2489c535da743 |
15 | 104150c096eab |
hex | 7825efed5837 |
132104334432311 has 4 divisors (see below), whose sum is σ = 132104384426400. Its totient is φ = 132104284438224.
The previous prime is 132104334432307. The next prime is 132104334432319. The reversal of 132104334432311 is 113234433401231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132104334432311 - 22 = 132104334432307 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132104334432319) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20798366 + ... + 26396603.
It is an arithmetic number, because the mean of its divisors is an integer number (33026096106600).
Almost surely, 2132104334432311 is an apocalyptic number.
132104334432311 is a deficient number, since it is larger than the sum of its proper divisors (49994089).
132104334432311 is an equidigital number, since it uses as much as digits as its factorization.
132104334432311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 49994088.
The product of its (nonzero) digits is 62208, while the sum is 35.
Adding to 132104334432311 its reverse (113234433401231), we get a palindrome (245338767833542).
The spelling of 132104334432311 in words is "one hundred thirty-two trillion, one hundred four billion, three hundred thirty-four million, four hundred thirty-two thousand, three hundred eleven".
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