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132104334432311 = 279911947194969
BaseRepresentation
bin11110000010010111101111…
…111011010101100000110111
3122022202001101012111110022122
4132002113233323111200313
5114303344134103313221
61144543520551550155
736553136362230113
oct3602275773254067
9568661335443278
10132104334432311
113910215191a27a
121299685638b35b
135893501612a27
142489c535da743
15104150c096eab
hex7825efed5837

132104334432311 has 4 divisors (see below), whose sum is σ = 132104384426400. Its totient is φ = 132104284438224.

The previous prime is 132104334432307. The next prime is 132104334432319. The reversal of 132104334432311 is 113234433401231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132104334432311 - 22 = 132104334432307 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132104334432319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20798366 + ... + 26396603.

It is an arithmetic number, because the mean of its divisors is an integer number (33026096106600).

Almost surely, 2132104334432311 is an apocalyptic number.

132104334432311 is a deficient number, since it is larger than the sum of its proper divisors (49994089).

132104334432311 is an equidigital number, since it uses as much as digits as its factorization.

132104334432311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49994088.

The product of its (nonzero) digits is 62208, while the sum is 35.

Adding to 132104334432311 its reverse (113234433401231), we get a palindrome (245338767833542).

The spelling of 132104334432311 in words is "one hundred thirty-two trillion, one hundred four billion, three hundred thirty-four million, four hundred thirty-two thousand, three hundred eleven".

Divisors: 1 2799119 47194969 132104334432311