Base | Representation |
---|---|
bin | 11110000010011000011010… |
… | …001110100010111111011011 |
3 | 122022202010012122212212220111 |
4 | 132002120122032202333123 |
5 | 114303402112243030243 |
6 | 1144544115222505151 |
7 | 36553163100343123 |
oct | 3602303216427733 |
9 | 568663178785814 |
10 | 132105044111323 |
11 | 3910248647a658 |
12 | 12996a13b951b7 |
13 | 58935b566083a |
14 | 2489cbd973c83 |
15 | 104154e52c39d |
hex | 78261a3a2fdb |
132105044111323 has 4 divisors (see below), whose sum is σ = 132915504504808. Its totient is φ = 131294583717840.
The previous prime is 132105044111317. The next prime is 132105044111351. The reversal of 132105044111323 is 323111440501231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132105044111323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132105044111123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405230196498 + ... + 405230196823.
It is an arithmetic number, because the mean of its divisors is an integer number (33228876126202).
Almost surely, 2132105044111323 is an apocalyptic number.
132105044111323 is a deficient number, since it is larger than the sum of its proper divisors (810460393485).
132105044111323 is an equidigital number, since it uses as much as digits as its factorization.
132105044111323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 810460393484.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 132105044111323 its reverse (323111440501231), we get a palindrome (455216484612554).
The spelling of 132105044111323 in words is "one hundred thirty-two trillion, one hundred five billion, forty-four million, one hundred eleven thousand, three hundred twenty-three".
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