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13210801377997 is a prime number
BaseRepresentation
bin1100000000111110000100…
…0111111001001011001101
31201202221101110111001211211
43000033201013321023031
53212421210123043442
644032543001414421
72532306654633346
oct300174107711315
951687343431754
1013210801377997
11423373aa78073
12159441279a411
1374aa08a0ac02
143395988730cd
1517d99b014617
hexc03e11f92cd

13210801377997 has 2 divisors, whose sum is σ = 13210801377998. Its totient is φ = 13210801377996.

The previous prime is 13210801377941. The next prime is 13210801378051. The reversal of 13210801377997 is 79977310801231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13199081366916 + 11720011081 = 3633054^2 + 108259^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13210801377997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13210801377097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605400688998 + 6605400688999.

It is an arithmetic number, because the mean of its divisors is an integer number (6605400688999).

Almost surely, 213210801377997 is an apocalyptic number.

It is an amenable number.

13210801377997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13210801377997 is an equidigital number, since it uses as much as digits as its factorization.

13210801377997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4000752, while the sum is 58.

The spelling of 13210801377997 in words is "thirteen trillion, two hundred ten billion, eight hundred one million, three hundred seventy-seven thousand, nine hundred ninety-seven".