Base | Representation |
---|---|
bin | 111101100001001011… |
… | …1101100101101000111 |
3 | 110121222222021220212001 |
4 | 1323002113230231013 |
5 | 4131030130324312 |
6 | 140405052010131 |
7 | 12354544365346 |
oct | 1730227545507 |
9 | 417888256761 |
10 | 132110011207 |
11 | 51033725849 |
12 | 2172b460947 |
13 | c5c5089385 |
14 | 65737ddb5d |
15 | 3683207057 |
hex | 1ec25ecb47 |
132110011207 has 2 divisors, whose sum is σ = 132110011208. Its totient is φ = 132110011206.
The previous prime is 132110011157. The next prime is 132110011273. The reversal of 132110011207 is 702110011231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132110011207 - 27 = 132110011079 is a prime.
It is a super-2 number, since 2×1321100112072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132113011207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055005603 + 66055005604.
It is an arithmetic number, because the mean of its divisors is an integer number (66055005604).
Almost surely, 2132110011207 is an apocalyptic number.
132110011207 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110011207 is an equidigital number, since it uses as much as digits as its factorization.
132110011207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 84, while the sum is 19.
Adding to 132110011207 its reverse (702110011231), we get a palindrome (834220022438).
The spelling of 132110011207 in words is "one hundred thirty-two billion, one hundred ten million, eleven thousand, two hundred seven".
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