Base | Representation |
---|---|
bin | 10011001110010111101… |
… | …101110110111100000101 |
3 | 11200021222202100211120011 |
4 | 103032113231312330011 |
5 | 133121103141402442 |
6 | 2450523301110221 |
7 | 164306045421463 |
oct | 23162755667405 |
9 | 4607882324504 |
10 | 1321100340997 |
11 | 46a303779738 |
12 | 1940559b8371 |
13 | 9776b742008 |
14 | 47d27a5b833 |
15 | 24571593117 |
hex | 13397b76f05 |
1321100340997 has 2 divisors, whose sum is σ = 1321100340998. Its totient is φ = 1321100340996.
The previous prime is 1321100340947. The next prime is 1321100341069. The reversal of 1321100340997 is 7990430011231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1280878434081 + 40221906916 = 1131759^2 + 200554^2 .
It is an emirp because it is prime and its reverse (7990430011231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1321100340997 is a prime.
It is a super-2 number, since 2×13211003409972 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321100340907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660550170498 + 660550170499.
It is an arithmetic number, because the mean of its divisors is an integer number (660550170499).
Almost surely, 21321100340997 is an apocalyptic number.
It is an amenable number.
1321100340997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321100340997 is an equidigital number, since it uses as much as digits as its factorization.
1321100340997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 40.
The spelling of 1321100340997 in words is "one trillion, three hundred twenty-one billion, one hundred million, three hundred forty thousand, nine hundred ninety-seven".
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