132110044214471 has 2 divisors, whose sum is σ = 132110044214472. Its totient is φ = 132110044214470.

The previous prime is 132110044214437. The next prime is 132110044214479. The reversal of 132110044214471 is 174412440011231.

It is a strong prime.

It is an emirp because it is prime and its reverse (174412440011231) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132110044214471 is a prime.

It is a super-3 number, since 3×132110044214471³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132110044214479) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055022107235 + 66055022107236.

It is an arithmetic number, because the mean of its divisors is an integer number (66055022107236).

Almost surely, 2^{132110044214471} is an apocalyptic number.

132110044214471 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110044214471 is an equidigital number, since it uses as much as digits as its factorization.

132110044214471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21504, while the sum is 35.

The spelling of 132110044214471 in words is "one hundred thirty-two trillion, one hundred ten billion, forty-four million, two hundred fourteen thousand, four hundred seventy-one".