Base | Representation |
---|---|
bin | 11110000010011101001001… |
… | …011000100100000000111111 |
3 | 122022202121100010022122202111 |
4 | 132002131021120210000333 |
5 | 114303443021314432112 |
6 | 1144550320032034451 |
7 | 36553433116562314 |
oct | 3602351130440077 |
9 | 568677303278674 |
10 | 132110130233407 |
11 | 3910465645a437 |
12 | 129979b3392a27 |
13 | 5893c162b4231 |
14 | 248a243252d0b |
15 | 104174ace65a7 |
hex | 78274962403f |
132110130233407 has 2 divisors, whose sum is σ = 132110130233408. Its totient is φ = 132110130233406.
The previous prime is 132110130233387. The next prime is 132110130233429. The reversal of 132110130233407 is 704332031011231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132110130233407 - 231 = 132107982749759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132110130233447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055065116703 + 66055065116704.
It is an arithmetic number, because the mean of its divisors is an integer number (66055065116704).
Almost surely, 2132110130233407 is an apocalyptic number.
132110130233407 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110130233407 is an equidigital number, since it uses as much as digits as its factorization.
132110130233407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 132110130233407 its reverse (704332031011231), we get a palindrome (836442161244638).
The spelling of 132110130233407 in words is "one hundred thirty-two trillion, one hundred ten billion, one hundred thirty million, two hundred thirty-three thousand, four hundred seven".
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