Base | Representation |
---|---|
bin | 111101100001001100… |
… | …0100000011100010000 |
3 | 110121222222200200112200 |
4 | 1323002120200130100 |
5 | 4131030204114440 |
6 | 140405100323200 |
7 | 12354546240231 |
oct | 1730230403420 |
9 | 417888620480 |
10 | 132110223120 |
11 | 5103385aa87 |
12 | 2172b543500 |
13 | c5c5131975 |
14 | 6573857088 |
15 | 3683249c30 |
hex | 1ec2620710 |
132110223120 has 240 divisors, whose sum is σ = 446805545472. Its totient is φ = 34981401600.
The previous prime is 132110223101. The next prime is 132110223121. The reversal of 132110223120 is 21322011231.
132110223120 is a `hidden beast` number, since 1 + 321 + 1 + 0 + 223 + 120 = 666.
It is a tau number, because it is divible by the number of its divisors (240).
It is a super-2 number, since 2×1321102231202 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 132110223093 and 132110223102.
It is not an unprimeable number, because it can be changed into a prime (132110223121) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 69494170 + ... + 69496070.
Almost surely, 2132110223120 is an apocalyptic number.
132110223120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132110223120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (223402772736).
132110223120 is an abundant number, since it is smaller than the sum of its proper divisors (314695322352).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132110223120 is a wasteful number, since it uses less digits than its factorization.
132110223120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2550 (or 2541 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 132110223120 its reverse (21322011231), we get a palindrome (153432234351).
The spelling of 132110223120 in words is "one hundred thirty-two billion, one hundred ten million, two hundred twenty-three thousand, one hundred twenty".
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