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13211022523 is a prime number
BaseRepresentation
bin11000100110111000…
…00011010010111011
31021002200212110221111
430103130003102323
5204024010210043
610022530021151
7645244560436
oct142334032273
937080773844
1013211022523
11566a306836
1226884177b7
1313270180ba
148d47ba81d
15524c3709d
hex3137034bb

13211022523 has 2 divisors, whose sum is σ = 13211022524. Its totient is φ = 13211022522.

The previous prime is 13211022511. The next prime is 13211022533. The reversal of 13211022523 is 32522011231.

13211022523 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13211022523 - 225 = 13177468091 is a prime.

It is a super-4 number, since 4×132110225234 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13211022494 and 13211022503.

It is not a weakly prime, because it can be changed into another prime (13211022533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605511261 + 6605511262.

It is an arithmetic number, because the mean of its divisors is an integer number (6605511262).

Almost surely, 213211022523 is an apocalyptic number.

13211022523 is a deficient number, since it is larger than the sum of its proper divisors (1).

13211022523 is an equidigital number, since it uses as much as digits as its factorization.

13211022523 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 22.

Adding to 13211022523 its reverse (32522011231), we get a palindrome (45733033754).

The spelling of 13211022523 in words is "thirteen billion, two hundred eleven million, twenty-two thousand, five hundred twenty-three".