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132110444010043 is a prime number
BaseRepresentation
bin11110000010011101011100…
…000101100001101000111011
3122022202122010222202011101101
4132002131130011201220323
5114303444142131310133
61144550411121232231
736553443646621102
oct3602353405415073
9568678128664341
10132110444010043
11391047a7593474
1212997a80492677
135893c662c6895
14248a272bb1039
15104176862737d
hex78275c161a3b

132110444010043 has 2 divisors, whose sum is σ = 132110444010044. Its totient is φ = 132110444010042.

The previous prime is 132110444010011. The next prime is 132110444010107. The reversal of 132110444010043 is 340010444011231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132110444010043 - 25 = 132110444010011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132110444009993 and 132110444010020.

It is not a weakly prime, because it can be changed into another prime (132110444010443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055222005021 + 66055222005022.

It is an arithmetic number, because the mean of its divisors is an integer number (66055222005022).

Almost surely, 2132110444010043 is an apocalyptic number.

132110444010043 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110444010043 is an equidigital number, since it uses as much as digits as its factorization.

132110444010043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 132110444010043 its reverse (340010444011231), we get a palindrome (472120888021274).

The spelling of 132110444010043 in words is "one hundred thirty-two trillion, one hundred ten billion, four hundred forty-four million, ten thousand, forty-three".