Base | Representation |
---|---|
bin | 11110000010011101100001… |
… | …001101111100010010110111 |
3 | 122022202122100222202002222020 |
4 | 132002131201031330102313 |
5 | 114303444331201234310 |
6 | 1144550423434404223 |
7 | 36553446043450302 |
oct | 3602354115742267 |
9 | 568678328662866 |
10 | 132110530102455 |
11 | 39104841145a23 |
12 | 12997aa5290673 |
13 | 5893c7b0ab038 |
14 | 248a2803c1b39 |
15 | 1041770e81170 |
hex | 78276137c4b7 |
132110530102455 has 16 divisors (see below), whose sum is σ = 218195456169984. Its totient is φ = 68186080052640.
The previous prime is 132110530102409. The next prime is 132110530102459. The reversal of 132110530102455 is 554201035011231.
It is not a de Polignac number, because 132110530102455 - 211 = 132110530100407 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132110530102459) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 142054332979 + ... + 142054333908.
It is an arithmetic number, because the mean of its divisors is an integer number (13637216010624).
Almost surely, 2132110530102455 is an apocalyptic number.
132110530102455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
132110530102455 is a deficient number, since it is larger than the sum of its proper divisors (86084926067529).
132110530102455 is a wasteful number, since it uses less digits than its factorization.
132110530102455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 284108666926.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 132110530102455 its reverse (554201035011231), we get a palindrome (686311565113686).
The spelling of 132110530102455 in words is "one hundred thirty-two trillion, one hundred ten billion, five hundred thirty million, one hundred two thousand, four hundred fifty-five".
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