Base | Representation |
---|---|
bin | 11110000010011110001010… |
… | …111101011110101111010111 |
3 | 122022202201011210112102222122 |
4 | 132002132022331132233113 |
5 | 114304002244442231132 |
6 | 1144551021133050155 |
7 | 36553502306235122 |
oct | 3602361275365727 |
9 | 568681153472878 |
10 | 132111230430167 |
11 | 3910507049955a |
12 | 1299805b92695b |
13 | 5894060203631 |
14 | 248a3094033b9 |
15 | 10417b26ba912 |
hex | 78278af5ebd7 |
132111230430167 has 2 divisors, whose sum is σ = 132111230430168. Its totient is φ = 132111230430166.
The previous prime is 132111230430061. The next prime is 132111230430187. The reversal of 132111230430167 is 761034032111231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132111230430167 - 218 = 132111230168023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132111230430187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055615215083 + 66055615215084.
It is an arithmetic number, because the mean of its divisors is an integer number (66055615215084).
Almost surely, 2132111230430167 is an apocalyptic number.
132111230430167 is a deficient number, since it is larger than the sum of its proper divisors (1).
132111230430167 is an equidigital number, since it uses as much as digits as its factorization.
132111230430167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18144, while the sum is 35.
Adding to 132111230430167 its reverse (761034032111231), we get a palindrome (893145262541398).
The spelling of 132111230430167 in words is "one hundred thirty-two trillion, one hundred eleven billion, two hundred thirty million, four hundred thirty thousand, one hundred sixty-seven".
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