132111240131041 has 4 divisors (see below), whose sum is σ = 139882489550532. Its totient is φ = 124339990711552.

The previous prime is 132111240131033. The next prime is 132111240131047. The reversal of 132111240131041 is 140131042111231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 117009738946816 + 15101501184225 = 10817104^2 + 3886065^2 .

It is a cyclic number.

It is not a de Polignac number, because 132111240131041 - 2³ = 132111240131033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132111240130997 and 132111240131015.

It is not an unprimeable number, because it can be changed into a prime (132111240131047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3885624709720 + ... + 3885624709753.

It is an arithmetic number, because the mean of its divisors is an integer number (34970622387633).

Almost surely, 2^{132111240131041} is an apocalyptic number.

It is an amenable number.

132111240131041 is a deficient number, since it is larger than the sum of its proper divisors (7771249419491).

132111240131041 is an equidigital number, since it uses as much as digits as its factorization.

132111240131041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7771249419490.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 132111240131041 its reverse (140131042111231), we get a palindrome (272242282242272).

The spelling of 132111240131041 in words is "one hundred thirty-two trillion, one hundred eleven billion, two hundred forty million, one hundred thirty-one thousand, forty-one".