Search a number
-
+
132111344133211 = 145191048479761
BaseRepresentation
bin11110000010011110010001…
…101111001110010001011011
3122022202201110201111011020111
4132002132101233032101123
5114304003013044230321
61144551040314105151
736553505156551642
oct3602362157162133
9568681421434214
10132111344133211
113910511969a313
1212998091a1b1b7
13589407a934341
14248a31a560359
1510417bc67a5e1
hex782791bce45b

132111344133211 has 4 divisors (see below), whose sum is σ = 132202392614424. Its totient is φ = 132020295652000.

The previous prime is 132111344133179. The next prime is 132111344133259. The reversal of 132111344133211 is 112331443111231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132111344133211 - 25 = 132111344133179 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132111344133011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45524238430 + ... + 45524241331.

It is an arithmetic number, because the mean of its divisors is an integer number (33050598153606).

Almost surely, 2132111344133211 is an apocalyptic number.

132111344133211 is a deficient number, since it is larger than the sum of its proper divisors (91048481213).

132111344133211 is an equidigital number, since it uses as much as digits as its factorization.

132111344133211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91048481212.

The product of its digits is 5184, while the sum is 31.

Adding to 132111344133211 its reverse (112331443111231), we get a palindrome (244442787244442).

The spelling of 132111344133211 in words is "one hundred thirty-two trillion, one hundred eleven billion, three hundred forty-four million, one hundred thirty-three thousand, two hundred eleven".

Divisors: 1 1451 91048479761 132111344133211